Problem 7-10
| The data in the table below represent time study observations for a woodworking operation. (Hint: See Solved Problems section.) |
|
|
OBSERVATIONS (minutes per cycle) |
| Element |
Performance
Rating |
1 |
2 |
3 |
4 |
5 |
6 |
| 1 |
110% |
1.20 |
1.17 |
1.16 |
1.22 |
1.24 |
1.15 |
| 2 |
115 |
0.83 |
0.87 |
0.78 |
0.82 |
0.85 |
1.32* |
| 3 |
105 |
0.58 |
0.53 |
0.52 |
0.59 |
0.60 |
0.54 |
|
| *Unusual delay, disregard time. |
| a. |
Based on the observations, determine the standard time for the operation, assuming an allowance of 15 percent of job time. (Round your intermediate calculations and final answers to 3 decimal places.) |
| Element |
Standard time |
| 1 |
[removed] |
| 2 |
[removed] |
| 3 |
[removed] |
|
| b. |
How many observations would be needed to estimate the mean time for element 2 within 1 percent of its true value with a 95.5 percent confidence? (Round your intermediate calculations to 3 decimal places and round up your final answer to the next whole number.) |
| Number of observations |
[removed] |
| c. |
How many observations would be needed to estimate the mean time for element 2 within .01 minute of its true value with a 95.5 percent confidence? (Round your intermediate calculations to 3 decimal places and round up your final answer to the next whole number.) |
| Number of observations |
[removed] |
woodworking operation was first posted on September 18, 2019 at 5:22 pm.
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